Recent content by skittlesj526

Thanks everyone for all your help. I really understand the ones that you helped me to work out! Thanks again!

A small bomb, of mass 12 Kg, is moving toward the North with a velocity of 5.0 m/s. It explodes into three segments: a 6.0 Kg fragment moving west with a speed of 9.0 m/s; a 4.0 Kg fragment moving East with a speed of 10 m/s; and a third fragment with a mass of 1.0 Kg. What is the velocity of...

i got it now!

how did you get 3.68m/s?

i now got l2.35l m/s (abs value)

should i convert that to 0.1542m/s? 9m (m)(-9.8)(.4873)+1/2(m)(v)2=1/2(m)(v)2

that would be cm/s

just seemd kinda large, doesn't it?

i got an ending velocity of 15.42 m/s

yeah, i got 48.73 cm which converts about the same but now i have: mgh+1/2 mv2=1/2 mv2 how will the masses cancel?

so now that i have the angle, i can set TEa=TEb. Does it start with PE and KE? so that... TEa=PE+KE and TEb=KE ?

yeah, SOH CAH TOA, right? but i don't even have an angle

yeah i see that the masses will cancel out...but there is one problem...i've never had trig and don't know where to begin with a trig formula...is there a name?

Well, i figured the first one out. I found the velocity of mass B prime and used it to find the velocity of mass A prime. I'm working on number 4 right now. I'm thinkin that total energy at point A is equal to total energy at point B but there is no mass or angle and I don't know how to...

Well, i do know that there is an elastic head-on collision which means change in momentum and conservation of KE.