Recent content by skyza

That's what I thought. Thanks!

Why did you add 48 to -46 and instead of adding 16?

I really appreciate the help. Some of my notes made me think to keep going, but I see how to do it now. I also figured out that I don't need to test each number. Thank you.

I've figured it out.

Alright, I've gotten to: -3(x-4)(x-4)=62 or -3(x-4)^2=62 or -3(x-4)^2 -62=0 What do I do from here?

This is how I've done it so far. I have to use synthetic division. I tried -1 & 1 and neither worked, so I tried 3

I tried completing the square for: f(x)= -3x^2 +24x-46 That's how I ended up with that. I divided 24/2 and added it to both sides and got -3x+144-sqrtof 190

Here's the problem I have to do: Let f(x)= x^3 -7x^2 +17x-15 One zero of f(x) is K=2-i find all others and write f(x) in a factored form. I ended up getting: f(x)= x^2 -x+2 Is this correct? Thanks

Thanks for the help. I'm trying to find the vertex of: f(x)= -3x^2 +24x-46 and I ended up with: -3x+144-sqrtof 190

I have to find the vertex, axis, domain, & range of this quadratic equation: f(x)= -1/2(x+1)^2 -3 I can't remember how to do the vertex. Is it y= -b/2a? Also, I tried factoring the equation, but I think I messed up. I ended up with: f(x)= .25x^2 +.5x-2.75 Thanks

I really appreciate all the help. I'm going to school to become a mechanical engineer, so I'm sure I'll be back with more questions.

Thanks for the help. I've finished all of my homework except ONE question. What is the range of this question: f(x) = √(x-1) +1 I know it's not (-∞, ∞) Is it [1, ∞)?

1. Is 1 the answer?

it's 1

3-2(1)^2 = -1