Recent content by smagro

thanks... summary: momentum is a vector quantity and direction has to be considered in working out the change in momentum. There is no argument about that.

what if the collision was an elastic collision. momentum before should be equal to the momentum after. so the gymnast should rebound with a speed of 6m/s. but if we work momentum, momentum (being a vector quantity), we get 40kg x 6.3m/s = 252kg/ms momentum after = 40kg x -6.3m/s =...

is it also good to argue that the upward force by the trampoline should be greater than the weight of gymnast?

some arguments against my working were that the gymnast change in momentum was from 0m/s to 5.7m/s because the gymnast was at rest at the maximum stretching point of the trampoline. this will make the change in momentum be 228kgm/s - 0 kgm/s = 228kgm/s. then the force is 228/0.50 = 456N...

Homework Statement A gymnast of mass 40kg is practising on a trampoline. The gymnast lands with a speed of 6.3m/s. The gymnast rebounds with a speed of 5.7m/s. a) Calculate the change in momentum of the gymnast b) The gymnast was in contact with the trampoline for 0.50s. Calculate the...