Recent content by Smusko
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Distance traveled of a ball dropped in water.
I am sooooo stupid it's almost depressing. Thank you.- Smusko
- Post #5
- Forum: Introductory Physics Homework Help
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Distance traveled of a ball dropped in water.
When you integrate that, what happes with v? v=0.9gt - cs? since ds/dt = v. It feels so wrong. Or do you treat v as a constant and v=0.9gt - cst? That also feels wrong.- Smusko
- Post #3
- Forum: Introductory Physics Homework Help
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Distance traveled of a ball dropped in water.
Homework Statement A steel ball is released at the surface of the ocean and it takes 64 minutes for it to hit the bottom. The balls downward acceleration is a=0.9g-cv where g=9.82 m/s2 and c = 3.02s-1 and v is the speed. What is the depth of the ocean where the ball was released? Homework...- Smusko
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- Ball Distance traveled Water
- Replies: 4
- Forum: Introductory Physics Homework Help
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Integrating zdS on a Sphere Centered at Origin
Dang, thought. Missed the ********* **** **** minus sign. I got sqrt(1-Sin2(t)) because (dz/dt) = -aSin(t). Thanks.- Smusko
- Post #7
- Forum: Calculus and Beyond Homework Help
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Undergrad Order and harmony vs disorder and chaos.
This is image is representative on how we think the universe looks on the largest scales. [PLAIN]http://upload.wikimedia.org/wikipedia/en/c/c0/Local_galaxy_filaments_2.gif from http://en.wikipedia.org/wiki/Galaxy_filament Looks pretty chaotic. -
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Undergrad Uncovering the Mystery: The Science Behind White Light and the Sun's Spectrum
I do not officially know what I'm talking about, but here goes. Maybe theoretically they don't cover every possible infinitesimal change in frequency, but enough to show us that it follows a mathematically smooth probability curve. And when you get the spectrum of a star it comes with a...- Smusko
- Post #9
- Forum: Astronomy and Astrophysics
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Integrating zdS on a Sphere Centered at Origin
I have checked with Wolfram on all the derivatives and integrals. The dS must be equal to a*cos(t)dt and if it is like you say that you put z=a*cos(t) and integrate from 0 to pi/2 then the integral should look like this: a2*Integral(cos2(t))dt = a2((t/2) + (1/4)*sin(2t)) Evaluated from 0 to...- Smusko
- Post #5
- Forum: Calculus and Beyond Homework Help
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Integrating zdS on a Sphere Centered at Origin
Yeah, helps allot. I have done it that way and failed but I have a knack for making stupid tiny mistakes, like forgetting a minus sign or something. So Il try again. It is nice to know that this stuff is not completely beyond me. :)- Smusko
- Post #3
- Forum: Calculus and Beyond Homework Help
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Integrating zdS on a Sphere Centered at Origin
I will denote vectors in bold. Homework Statement Show that the curve C given by r=a*Cos(t)Sin(t)i+a*Sin2(t)j+a*Cos(t)k ( 0=<t=<pi/2 ) lies on a sphere centred at the origin. Find \int zdS under C *edit* There is a huge gap here and the equation has dissapered for me. But...- Smusko
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- Origin Sphere
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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Change of variable in triple integrals
Of course. How stupid of me. I think I have solved it now. I tried again with the new limit and failed, but then I noticed that I by mistake took the square of something that should not be squared. When I correct that mistake it should work out. The source of error in these calculations are...- Smusko
- Post #10
- Forum: Calculus and Beyond Homework Help
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Change of variable in triple integrals
Ahhhhhh. Now I see... I think. How do I do to form an expression for w then? Or get its limit.- Smusko
- Post #8
- Forum: Calculus and Beyond Homework Help
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Change of variable in triple integrals
Actually the height is dependent on t. It is a cylinder and R and theta only decides the area of the circle. So that can't be what's wrong. What I'm not 100 percent sure of is the limit.- Smusko
- Post #6
- Forum: Calculus and Beyond Homework Help
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Change of variable in triple integrals
You are right. I'l check into that. Thanks.- Smusko
- Post #5
- Forum: Calculus and Beyond Homework Help
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Change of variable in triple integrals
Thanks, you are right. a and b are supposed to be squared in the problem statement. I'll edit it right away.- Smusko
- Post #3
- Forum: Calculus and Beyond Homework Help
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Change of variable in triple integrals
Homework Statement Solve for the volume above the xy-plane and below the paraboloid z=1-x2/a2-y2/b2 I have gotten an answer that is close to the correct one, but I can't figure out where I am wrong. Homework Equations Solution: Volume is = ab\pi/2 The Attempt at a Solution...- Smusko
- Thread
- Change Integrals Triple integrals Variable
- Replies: 9
- Forum: Calculus and Beyond Homework Help