Recent content by snoopyrawr

so it would be like this: W=KEf-KEi (KEf= kinetic final, KEi= kinetic initial) W=(1/2(20kg)(2.6m/s)^2)-(1/2(20kg)(0.5m/s)^2) W=65.1 J is there another step i have to do?

yes there is a horizontal force of 30degrees applied on the box and how would you set up this problem if the friction coefficient is not given?

Homework Statement i've been stuck on this problem for about 45mins. A constant external force P = 160 N is applied to a 20 kg box,which is on a rough horizontal surface. The force pushes the box a distance of 8.0 m, in a time interval of 4.0 s, and the speed changes from v1 = 0.5 m/s to v2 =...