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Ssongoku reacted to Gavran's post in the thread Finding the number of ways to arrange identical balls in a circle (3 different colors) with
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You do not need any formula to solve this problem. With two blue balls and two red balls you have two cases BBRR and BRBR. How many... -
Ssongoku reacted to JimWhoKnew's post in the thread Finding the number of ways to arrange identical balls in a circle (3 different colors) with
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For the case 1 yellow, 2 red, 2 blue, I get 6 arrangements in a circle, which is the same as (5-1)!/(2!2!1!) . How many do you get? For... -
Ssongoku reacted to PeroK's post in the thread Finding the number of ways to arrange identical balls in a circle (3 different colors) with
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The idea of fixing the yellow ball is that it picks out the set of solutions that cannot be equivalent under rotation. If there were... -
Ssongoku reacted to JimWhoKnew's post in the thread Finding the number of ways to arrange identical balls in a circle (3 different colors) with
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Let's take a closer look at your 2 red balls and 2 blue example. The number of combinations for arranging them in a row is 4!/(2!2!)=6... -
Ssongoku reacted to WWGD's post in the thread Finding the number of ways to arrange identical balls in a circle (3 different colors) with
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And assume balls of the same color are undistinguishable, i.e. , b1b2= b2b1, etc.? -
Ssongoku reacted to PeroK's post in the thread Finding the number of ways to arrange identical balls in a circle (3 different colors) with
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I assume that two arrangements are considered equal if they are equal after rotation? If so, you could start by fixing the position of... -
Ssongoku replied to the thread Finding the number of ways to arrange identical balls in a circle (3 different colors).Yes. Let R = red ball and B = blue ball. Arrangement of BBRR in circle will be the same as BRRB So, the strategy is to list all the...
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Ssongoku posted the thread Finding the number of ways to arrange identical balls in a circle (3 different colors) in Precalculus Mathematics Homework Help.I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so...