Recent content by soul814

Yep I got 60 degrees 59.9 i think. Thanks for your help :D nice i think i got section 3.2 and 3.3 of my textbook down ahah... tommo I will probably ask about projectile motion, hopefully you'll help me again. The textbook leaves out a lot of information. Like it leaves out little steps.

OOO I got it :D extend the Line downward so the verticles of the triangle are tan^-^1 = 4.5/2.6 (0,0) --> (2.6,0) --> (2.6,4.5)

the figure isn't a right triangle though

ummm I know all the measurements of the sides yet no angles except that 30 degrees, but its on the outside

wohoo got B) correct how would you get the degree though?

ahh indeed it does.. this makes sense now :D yes I learned cos(30) = 3/2 in precalculus the 30-60-90 triangle

how did u get the resultant vector?

i get .8660254038 *3 = 2.598076211 How would you get the answer after that? Rx = Ax + Bx = 2.6 + 0 Ry = Ay + By = 1.5 + 3 Now I add Rx + Ry = 7.1 Answer in book is 5.2m at 60 above x-axis

umm i did that... i get a different answer from the book (2.6,1.5) the other one is three but the same thing can be done to found it 3cos(90),3sin(90) (0,3)

this one isn't hw, i just want to get a better understanding of how to do it. the answers in numbers and there's a degree angle too. I know how to move it but then you can't do the theorem with this. ...| ...| ^...| |.../ |.../ |../ |/ ----------- >

yep lol now there's this odd problem that I've been trying to solve but I can't get it. The answers in the back of the book but there's no explanation. Each of the displacement vectors A and B shown in Figure P3.3 has a magnitude of 3. Graphically find (a) A + B (b) A - B (c) blah blah (d)...

ahh after looking at your diagram it should be 40^2 + 15^2 = c^2 about 43 then

Ahh I see you calculate this /\---> |.../ |../ |./ |/X and to calculate that you would have to shift the vectors .../\ .../.| ../..| ./...| /X..| therefore its still tan = 4/3

(3,4) is (x,y) so X-Axis is 3 and Y-Axis is 4

actually the angles different since tan = opp/adj so its tan^-^1 = 3/4