Recent content by spartacus

lol, i'll definitely get clarification from my teacher monday morning

i mean having Ncostheta=mg for the vertical and Nsintheta-mu*mg*sintheta=(mv^2)/r for horizontal

If it's parallel should i use mu*mg sintheta then because that would make the problem a lot more difficult

No, it's an online assignment The way i solved it, i just used the data to find which angle it would be at that speed

i have it right here let ill upload a screenshot

It's not a multipart problem no, how would i incorporate force of friction? would it be mg sintheta-mu?

Please don't give up on me, i easily did the other questions from this problem set, this question shouldn't be too hard, i just don't know what i did wrong

I believe the question means maximum control on the road that has the coefficient of friction of .2 or else why would mu be provided and yes

Why wouldn't i include friction? Didnt i consider the direction being against the horizontal normal force by subtracting it in N*sinθ-mgµ=(mv^2)/r

I figured N*sinθ is equal to centripetal force so it would by definition be going in the opposite direction of friction

ya so could you help me see what i did wrong?

Sorry, i meant that as a relevant equation in one dimension, since it's not accelerating vertically

Homework Statement 50.5 m radius 19 m/s speed µ = 0.2 acceleration due to gravity is 9.8 m/s2 At what angle θ should it be banked for maximum control of the racing car? Homework Equations sum of total forces=0? The Attempt at a Solution N*cosθ=mg N*sinθ-mgµ=(mv^2)/r mg*tanθ-mgµ=(mv^2)/r...