Recent content by spazticbutter

Actually, I take that back. There is a second part to the problem. I have to use Euler's method to approximate at several values of t. I take it I need to first solve for y in this IVP problem so I can use it in Euler's method. Any ideas on how I'm supposed to do this?

I don't know if I HAVE to solve in terms of y, but all the examples/problems that we've done in class have been in that form so I really don't know. So I take it there is no real way of finding it it in terms of y on the left hand side?

Um...ACTUALLY I have one more question. First off, I accidentally made a typo...it's actually 5 - 3(y^(1/2)) NOT 3 - 5(y^(1/2)). Second, after I took the integral of 1/(5-3(y^(1/2))) I got (-10/9)ln l 5 - 3(y^(1/2)) l + (2/9)(5-3(y^(1/2))) = t + C. How would I solve for y in this case? Any...

DOH! haha. Ok I see it now. For some reason it didn't work last night (I must have been tired). I was able to fully integrate. Thanks so much guys for your help! (and your patience :) )

Ok. Maybe I just made a simple mathematical error the first time around. Let me give it another try and I'll get back to you.

Any hints as to what that substitution might be? I've tried letting u = 3-5(y^(1/2)) and u = y^(1/2) and I've even tried multiplying top and bottom by 3 + 5(y^(1/2)) in order to remove the square root from the bottom. Nothing has worked for me so far...I must be missing something really obvious.

I know how to do the integrating factor method, but not with this problem. How would i get rid of the square root so as to have this in its linear form? (dy/dt + p(t)y = g(t))

Will you demonstrate how to do this? or get me started? Maybe it's obvious but I can't seem to figure it out.

That is correct (the y^1/2 is a square root but I can't really type that). I've learned the integrating factor method, I believe, but not variation of parameters. Try explaining what you're thinking and I'll see if I understand or recognize what I have learned :)

Homework Statement Solve the initial value problem where y(0) = 2.Homework Equations dy/dt = 3 - 5(y^(1/2))The Attempt at a Solution I tried the separable equation method but when it came time to take the integral of 1/[3 - 5(y^(1/2)], every solution I got became too complex to solve for y...