URGENT HELP! Initial Value Problem Question-Differential Equations and Euler's Method
Homework Statement
This is just an extension of an earlier thread. I see now that they want me to use Euler's method so it might change the way I do the problem.
The problem wants me to solve the initial...
Actually, I take that back. There is a second part to the problem. I have to use Euler's method to approximate at several values of t. I take it I need to first solve for y in this IVP problem so I can use it in Euler's method. Any ideas on how I'm supposed to do this?
I don't know if I HAVE to solve in terms of y, but all the examples/problems that we've done in class have been in that form so I really don't know.
So I take it there is no real way of finding it it in terms of y on the left hand side?
Um...ACTUALLY I have one more question. First off, I accidentally made a typo...it's actually 5 - 3(y^(1/2)) NOT 3 - 5(y^(1/2)). Second, after I took the integral of 1/(5-3(y^(1/2))) I got (-10/9)ln l 5 - 3(y^(1/2)) l + (2/9)(5-3(y^(1/2))) = t + C. How would I solve for y in this case? Any...
DOH! haha. Ok I see it now. For some reason it didn't work last night (I must have been tired). I was able to fully integrate.
Thanks so much guys for your help! (and your patience :) )
Any hints as to what that substitution might be? I've tried letting u = 3-5(y^(1/2)) and
u = y^(1/2) and I've even tried multiplying top and bottom by 3 + 5(y^(1/2)) in order to remove the square root from the bottom. Nothing has worked for me so far...I must be missing something really obvious.
I know how to do the integrating factor method, but not with this problem. How would i get rid of the square root so as to have this in its linear form? (dy/dt + p(t)y = g(t))
That is correct (the y^1/2 is a square root but I can't really type that).
I've learned the integrating factor method, I believe, but not variation of parameters.
Try explaining what you're thinking and I'll see if I understand or recognize what I have learned :)
Homework Statement
Solve the initial value problem where y(0) = 2.Homework Equations
dy/dt = 3 - 5(y^(1/2))The Attempt at a Solution
I tried the separable equation method but when it came time to take the integral of
1/[3 - 5(y^(1/2)], every solution I got became too complex to solve for y...