Recent content by sportcardinal90

The beam is TiH

It would have fewer ions since they each have more charge. So I would divide by 3, right?

actually, before i get to that, what if my charge state were different? Instead of -1, what if it were say, +3? Would my answer be what I just got but times 3?

So now that I have all of that, how do I calculate the dose?

Sorry, I mean 6.24e11 ion/cm^2/s. Good so far?

My mistake, so its 6.24e11 ions/cm^2/s right?

So I have 6.24e10 ions/second. Then I can calculate the fluence (ions/cm^2/second) by just dividing by the area right? Since I have area is 10 mm^2, convert to cm^2 and I get 6.24e13 ions/cm^2/s. Am I still correct so far?

So the number of ions is 10 nAmps/1.6e-19? So 10 nAmps = 10x10^-9 Amps. Then divide by 1.602e-19 and I get: 6.24e10 ions/second?

Do I divide by 1.6e-19, the elementary charge?

I gave my answer and then you just asked another question, so I am not sure where to go from here. You did not say if I was right or wrong.

Fair enough, do you think you can help me with this?

I don't know. I just know that is the "charge state" I am very lost, and why I am asking here

The charge state of TiH is -1. The charge state of the ion beam

Since the current is C/s and I have a charge state of -1, wouldn't C/s be identical to ions/s? Then I divide by area to get ions/s/cm^2?

Homework Statement I want to calculate the flux, fluence,and dose and I know several things: Beam energy = 40 keV Current = 10 nAmps Irradiated area = 10 mm^2 Time irradiated = 15 minutes Beam is made up of TiH with a charge state of -1 The material being irradiated is TiO2. Homework...