Dear all, I officially passed all of my exams yesterday. It seemed very unlikely but now I get to study physics and hopefully pursue my childhood dreams. I want to really thank you. I quit my job and was on a budget so that I couldn't afford tutoring, but I don't think I would have been able to...
Hi Kuruman,
thank you for answering me again. That makes sense.
The loop is originally falling vertically down perpendicular to the magnetic field. It's why when I thought about it I imagined the dipole being created inside the loop, directly opposite the direction of the magnetic field which...
Hi all, I'm sorry I just thought about this problem a little more and have another question.
Though it is a square, can I not see this wire as a loop and thus, wouldn't it also create a magnetic dipole that could end up feeling a torque?
Because by lenz's law the current induced should be in...
Hi mjc123 and drclaude.
Thank you for explaining. I have come across the equipartition theorem in halliday's textbook (which I got after this problem because I haven't come across the various C_v before).
I think I have a better idea now, but I'll have to ponder on it a bit more to really...
Hi, thanks drclaude.
I'm sorry if I'm misunderstanding something here.
I was just wondering since the kinetic energy is ## \frac {1}{2}m(v_rms)^2 = \frac {3}{2}kT ## it seemed to me like temperature is only dependent on kinetic energy.
And I was wondering why there isn't accounted for...
Hi mjc123, sorry to come back to this thread again after such a long time.
thanks to you and chestermiller I think I have a real good grasp and can use these formulas well (I did a lot of problems I found in two textbooks).
I still have a concept question though and it might be a silly...
Hello TSny.
Thank you very much. I lost quite a bit of time there. (trying to find a formula to make the masses cancel)
And I thought about it for the past two days without figuring it out.
I thought about it and with the density I probably could have figured it out. (Volume being 4a times A)...
Hi all, so I had this problem and on the exam and I got a solution but I had an mass-term in there which wasn't given.
I used Farraday's Law of Induction to get the Voltage induced.
Then I used ##rho* \frac{A}{4a} ## for the resistance and divided the Voltage by that to get the current.
I then...
Omg! You're right doggydan42, I evaluated e^0 as 0 instead of 1. I made this mistake each time I solved it. It's so frustrating, these simple things seem to still happen to me so often. (This morning I was working on another problem where I kept 2*1 = 3 and couldn't figure out what I was doing...
Hi @doggydan42 thank you.
I tried to make a clean version of what happened. I didn't upload the work previously because once i get confused it becomes a mess that only I can read.
First is the integrating factor.
I was able to solve the latter for the right solution, though if I use -dV/dt for...
I think I might be making an integration mistake.
Is ## V_0 = CR*\frac{dV}{dt} +V ## the correct Differential equation?
edit: I am definitely making integration mistakes. Sorry! I thought I had to use the integrating factor. And then used u sub. But with some algebra now, I could do without and...
Hi vela,
thank you very much. It seems like your earlier comment put me on the right track but I messed up somehow. I tried replacing I in IR through and the Resistance canceled and I ended up with the V_0 = V expression.
I will try to think about it some more and see if I can't come up with...
Hi @vela thank you very much.
the current was more intuitive, I knew it's dq/dt so it just came.
I did some algebra (Q to the dq/dt side) and then I integrated and then raise to the power of e to get Q out of the natural log to get the Result.
dq/dt is changing due to the amount of charge on...