Recent content by sriceb01

Use exactly what tnutty has written here for positive and negative values. Dont worry about the final, I don't know if anyone is going to do well on it, its bad if I am aiming for a 50% on it...

r=(-2*M_e*G*R_e)/(v^2*R_e-2*G*M_e) r=(-2*7e22*6.7e-11*1.75e6)?(500^2*1.75e6-2*6.7e-11*7e22) r=1.84e6 Good luck with your test today, I've been up all night studying for it, hope this helps!

for part d) you multiply torque calculated in part c) by the change in time

Common mistake

part b) torque=abs(R)*abs(F)*sin(90) =R*F*1=.1*12=1.2 should work

alrite for part a) L(rot) = Iw w=40rad/s (given in problem) I=.5*.7*.1^2=.0035 L=.0035*40=.14

Look at page 5 in the following article link... http://www.physics.gatech.edu/academics/Classes/spring2007/2211/mn/main/instructors/Curtis/lecture31.pdf A common mistake, one that i did myself, is to forget to convert 10 cm to meters...hope this helps

the only thing I am stuck on is the e internal

alrite man thanks!

No, sorry I am mean on question #3 where you got stuck...I got #1

Yea man, I am in 172 and on webassign, I am stuck at the same spot you are.

For part e) take the difference between the kinetic energy of the bullet plus the block before the collision and the kinetic energy of the bullet plus the block after the collision to get the answer. f) it happens so fast, that q is negligible.

Try 1/2 *(m1+m2)*vf^2...this should work

solved for Ethermal = 248.4 / Ke or 248.4/(1/2mv^2) using v found above i get 1.1613 J but that is wrong. where did i mess up?? Instead of dividing by Ke...You have to subtract by Ke.

What if you don't know the mass of the comet, because don't you need this to use the gravitational PE?