Recent content by srsthsr

so r u saying that (dV/dt)/B is v? and i just put that into the equation and i get the constant? also, is the P in Bernoulli's equation the same as pgh?

AHHHH, I am going crazy =/... ok L^3/T is the rate of flow... but we want velocity... so do i times it by 1/h? i don't know... and what does the gradient represent, i understand that its Adh/dt so what does Adh/dt mean? =[ this is confusing me so much i don't know what to do!

the area of the hole!

OKAY, will do that, i have a plotted graph already, however, isn't the relationship parabolic? or is it a straight line? once i get dV/dT which is A(dh/dt) then do i divide the answer by A and then that would give me dh/dt or in english, rate of change of height per time... which is the...

then what should i do? I am so confused ;(

Okay I tried out your equation, but the constant from Bernoulli's equation keeps changing. Could you please tell me what I did wrong? 1) Flow rate of 0.8L (0.8e-3)/30.38=2.63e-5(m^3/s) 2)speedxarea(of hole)=volume/time so speed=2.63e-5/0.0056x2x3.1416=7.484e-4 3) P=pgh=1x9.81x0.1445=1.417545...

OK, I will give it a try, I think I've found out what you meant =P thank you! will reply soon =]

Thank you for the rapid response, the problem is though, that the speed is not constant and varies as pressure and volume changes doesn't it?... how would I find the average speed?

okay... in English... the bigger the hole the more amount of water leaks out in a certain amount of time. The greater the depth, the more pressure, also the more amount of water leaking out... I get it, but i can't find an equation to relate all of them together and prove that the numbers that...

I am sooooooo sorry for the late reply I still however don't get it, i mean the depth? and the size of the hole? I am really confused :cry: i can't seem to find out the equation anywhere! i don't even know where to start looking =[... Thank you so much for helping me out!

Thank you so much for the reply. However, I think I am missing something out. if V=Ah then dV/dt = Adh/dt + hdA/dt right? how does it relate to B which is the cross section area of the hole? I am missing something out I found out that the hight at Vol 800ml is 14.45 cm, the radius of the bottle...

To all who have given up their time to help. Could you please have a look at my experiment, I am really stuck with this and don't know how to go on with it. I am unable to find a suitable equation to prove it mathematically as there is a varying change in both time taken and the pressure inside...