Alright so if I lable the force between 4kN and 10kN F1 and from 10kN to 8kN F2 and place an pivot at the left hand side of the bridge would this be correct and what would the equation be for the clockwise rotation= counter clockwise rotation ?
As seen below...
So if I replace L with 2 I get T=600/sin50 meaning T=783.
Now im stuck with the following question http://img63.imageshack.us/img63/5889/klrk3.th.jpg [Broken].
I cant seem to understand how to work the answer out.
Ah yes I see if we replace L with 1 we get 1.5=1.5 meaning the formula becomes 300*L=L*T*Sin30 meaning T=600N.
The next question im stuck on is http://img63.imageshack.us/img63/4524/yhse1.th.jpg [Broken]
I would think the answer is 300*L=L*T*Sin50 .