Recent content by ssj

Yes, but what does that stand for is there no specific term ?

Homework Statement In the formula vsquared= usquared+ 2as what does vsquared represent ?

I think the total Clockwise force F1 would be equal to 22kN*21m=462 correct but what would the counter clockwise force be then?

Alright so is this correct ? Meaning that ths distance from the pivot is 5.25M+5.25M?

Would it be *F1 14kN*10.5M=8kN*5.25M*F2 ? am I correct ?

Alright so if I lable the force between 4kN and 10kN F1 and from 10kN to 8kN F2 and place an pivot at the left hand side of the bridge would this be correct and what would the equation be for the clockwise rotation= counter clockwise rotation ? As seen below...

So if I replace L with 2 I get T=600/sin50 meaning T=783. Now I am stuck with the following question http://img63.imageshack.us/img63/5889/klrk3.th.jpg . I can't seem to understand how to work the answer out.

Right so the equation now becomes 300*L=L/2*T*Sin50.

Sorry about that I meant Sin50.

So this would make it 300*L=L/2*T*Sin30 ?

Ah yes I see if we replace L with 1 we get 1.5=1.5 meaning the formula becomes 300*L=L*T*Sin30 meaning T=600N. The next question I am stuck on is http://img63.imageshack.us/img63/4524/yhse1.th.jpg I would think the answer is 300*L=L*T*Sin50 .

For the sum of the clockwise torques I understand that 200*L+200(L/2) but I don't understand 200*(3L/2) where did the "3L" come from ?

How did you get "3L/2" on the right hand side and why isit L/2 on the left side ? Furthure more once I calcualted this euqation L=200 where do I go from here?

Right this makes it 400*L/3=L*T*Sin30

So the torque from question 1 was 400N and question 2 was 200N meaning we have 600*L/2=L*T*sin30.