Recent content by ssj

  1. S

    Vsquared= usquared+ 2as

    Yes, but what does that stand for is there no specific term ?
  2. S

    Vsquared= usquared+ 2as

    Homework Statement In the forumla vsquared= usquared+ 2as what does vsquared represent ?
  3. S

    Calculate the tension in the string

    I think the total Clockwise force F1 would be equal to 22kN*21m=462 correct but what would the counter clockwise force be then?
  4. S

    Calculate the tension in the string

    Alright so is this correct ? Meaning that ths distance from the pivot is 5.25M+5.25M?
  5. S

    Calculate the tension in the string

    Would it be *F1 14kN*10.5M=8kN*5.25M*F2 ? am I correct ?
  6. S

    Calculate the tension in the string

    Alright so if I lable the force between 4kN and 10kN F1 and from 10kN to 8kN F2 and place an pivot at the left hand side of the bridge would this be correct and what would the equation be for the clockwise rotation= counter clockwise rotation ? As seen below...
  7. S

    Calculate the tension in the string

    So if I replace L with 2 I get T=600/sin50 meaning T=783. Now im stuck with the following question http://img63.imageshack.us/img63/5889/klrk3.th.jpg [Broken]. I cant seem to understand how to work the answer out.
  8. S

    Calculate the tension in the string

    Right so the equation now becomes 300*L=L/2*T*Sin50.
  9. S

    Calculate the tension in the string

    Sorry about that I meant Sin50.
  10. S

    Calculate the tension in the string

    So this would make it 300*L=L/2*T*Sin30 ?
  11. S

    Calculate the tension in the string

    Ah yes I see if we replace L with 1 we get 1.5=1.5 meaning the formula becomes 300*L=L*T*Sin30 meaning T=600N. The next question im stuck on is http://img63.imageshack.us/img63/4524/yhse1.th.jpg [Broken] I would think the answer is 300*L=L*T*Sin50 .
  12. S

    Calculate the tension in the string

    For the sum of the clockwise torques I understand that 200*L+200(L/2) but I don't understand 200*(3L/2) where did the "3L" come from ?
  13. S

    Calculate the tension in the string

    How did you get "3L/2" on the right hand side and why isit L/2 on the left side ? Furthure more once I calcualted this euqation L=200 where do I go from here?
  14. S

    Calculate the tension in the string

    Right this makes it 400*L/3=L*T*Sin30
  15. S

    Calculate the tension in the string

    So the torque from question 1 was 400N and question 2 was 200N meaning we have 600*L/2=L*T*sin30.
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