Recent content by stackemup

I have finally worked it out and now understand it. Can you please review my below answer to find the power transferred if the max tension is halved to 4kN. F1 = 4000N F1/F2 = e^(μθ/sin⁡α ) 4000/F2 = e^((0.4 x 2.722)/sin⁡20 ) 4000/F2 = e^3.1834 4000/F2 =24.1296 F2= 4000/24.1296 F2= 165.7715...

Can anyone advise?

Still struggling to understand. If I take the angular velocity calculated above, I need to multiply this by the torque and effective radius to achieve the power transmitted into the second pulley, correct? I'm assuming that in the answer previously calculated in the other thread, uses the...

I'm unsure on how to calculate the above. I have found that to calculate the power, the net torque is multiplied by the angular velocity and radius. Is this correct ? Motor speed = 250 rev min -1 Angular velocity = (250 x 2pi) / 60 = 26.18 rads -1 Is this correct so far?

Anyone :)

Homework Statement From the below information provided, I have to calculate the power which has been transferred to the second pully. 2 pulley system, first pulley has a diameter of 150mm and driven by an electric motor at 250 rev min -1. , second pulley has a diameter of 400mm and is driven...

I have now found the solution. Thanks for the help.

SteamKing, can you please advise where I need to progress to from this?

In that case, to answer your question, yes i know how to calculate the bending moment(s) of the beam.

I have calculated the bending moments at 1m intervals but I am not sure about calculating the internal moment?

anyone

Homework Statement I need to plot a graph showing the deflection of the beam across its length giving a value of x at every 1m. The youngs modulus for the beam is 210 GNm^-2 and the moment of inertia is 54 X 10^-7 m^4 Homework Equations Really unsure where to start on this one. I have found...

Thanks.

I am a litte confused now. Is my post 18 correct?

I believe the lateral strain multiplied by the diameter gives the increase in diameter. The lateral strain is obtained from poissons ration, and the positive sign determines an increase in lateral dimensions, which is expected when an object is under compression.