Recent content by std10093

Now i saw what you posted.I did not knew.It's my first semester at university and my first lessons of linear algebra.Professor gave that exercise only to me in order to find it myself.I did'n know what trace is ,so what i named as main diagonal ,finally is the trace(this is what i was told by...

I found the solution! :approve: trace(AB-BA)=trace(I) trace is linear so trace(AB) - trace(BA) = trace(I) Easily we prove that trace(AB)=trace(BA) so we get the following equation 0= n * 1 ,n is the dimension of matrices n x n This of course is incongruous.

Homework Statement A and B are two matrices n X n Homework Equations AB-BA=identity matrix It is critical for me to prove that the are no matrices that are capable to hold the above equation true The Attempt at a SolutionI made several efforts.I had the idea to get the main...