Recent content by steve snash

Homework Statement 1 ⌠ | 10^(1/2)*(x^5)+(5*x^(1/5)) | dx ⌡ −1 Homework Equations once the absolute value is gone you can just integrate the function The Attempt at a Solution how do you get rid of the absolute, and how do you then integrate it, do you use the product rule...

that comes out with (4x-1)^4 (1256 x+2101) which is wrong, anybody else no how to simplify this problem?

Homework Statement simplify the following equation ((20*(4*x-1)^4)/(3*x+5)^7)-((4*x-1)^5/(21*(3*x+5)^8)) The Attempt at a Solution i took (4*x-1)^4)/(3*x+5)^7) as a common factor and ended up with (4*x-1)^4)/(3*x+5)^7)*(20-((4*x-1)^5/(21*(3*x+5)^8))) can someone show me how to...

sorry i ment ((3*cos(3*x))*(cos(6*x)))+((6*sin(-6*x))*(sin(3*x))) but its still wrong, can you simplify this?

that makes the answer (f o g)'(-2)= f(-2)(g(-2))(g'(-2)) = -1(-4)x(1) which = 4 which is the wrong answer =(

Homework Statement a) (f ° g)′(−2) = ? b) (g ° f)′(2) = ? Homework Equations f(−2) = −3, g(−2) = −4, f(2) = 3, g(2) = −3, f ′(−2) = −1, f ′(−4) = −2, f ′(2) = 5, g ′(−2) = 1, g ′(2) = 2, g ′(3) = −4. The Attempt at a Solution I have no idea how to do it every thing I've tried...

wtf, it still says its wrong, ((3*cos(3*x))*(6*cos(6*x)))+((6*sin(-6*x))*(3*sin(3*x))) what am i still doing wrong?

cheers

Homework Statement Find dy/dx, given y = sin( 3 x ) cos( 6 x ) Homework Equations product rule= f'g+g'f The Attempt at a Solution I used the product rule and got this, but its supposedly wrong, what have i done wrong?((3*cos(x))*(6*cos(x)))+((6*sin(-x))*(3*sin(x)))

so it works out to be, ((x+3)^6)*((9x^2)+(86x)+205) cheers for the help

so i could go, (2*x+10)*(x+3)^7+(7x+21)*(x+5)^2 then (3x+13)^7+(8x+26)^2

Homework Statement Differentiate the following function with respect to x, p(x) = (( x+5 )^2)*(( x+3 )^7) Homework Equations well the product rule is, p(x)=(f)*(g) p'(x)= (f')*(g)+(g')*(f) and general differentiation is, p'(x)=n(f)^(n-1)*n(g)^(n-1) The Attempt at a Solution well...

Thanks man

Homework Statement (For those values of x for which a solution exists), solve the following equation for y 3e^(2y−8) = (2x^5)−3 Homework Equations 1. xln e= x The Attempt at a Solution 1.3e^(2y−8) = (2x^5)−3 2.e^(2y−8) = ((2x^5)−3)/3 3.(2y-8)ln e = (ln (2x^5)-3)/3 4.(2y-8) = (ln...

really, sweet ty hallsofivy