Recent content by Steve4Physics

I don’t think that’s correct – there will be discontinuities in charge-densities and field-strengths as you move left to right. To add what @mjc123 said, I think the system should be visualised like this:

FWIW, on the right-hand side you are adding quantities with different dimensions: ##v## has dimensions ##LT^{-1}##, ## \frac {dv}{dt}## has dimensions ##LT^{-2}## and ##vgx## has dimensions ##L^3 T^{-3}##.

@NTesla, maybe this is one source of your difficulty... That's not entirely correct. The horizontal section of the chain is accelerated by tension,T, acting at its right-most end: We have to treat the falling vertical chain section as if there are only two forces acting on it*. The forces...

Do you mean the equations from your Post #1? I can see them. Here's a copy, though LaTeX rendering may be a problem:

@NTesla, the last part of the question on the screenshot is missing. So here’s what (I believe) it should say: "... At a certain moment, end-A of the chain is released. What is the speed of end-A when it reaches the right-hand end of the tube?" Are you sure about that? Suppose the whole...

Assuming that's not rhetorical... You can’t. But there’s a possibility that a 60° angle was accidentally omitted from the question - this would explain official answer. What you can do, at the start of your answer, is to make clear any assumption(s) you need to make. E.g. “No information is...

1.15mm is a bit thin to call a rope! A ‘cord’ might be a better term. Nylon is stretchy, but this won’t affect the answer to the question. You don’t need the Young modulus and you don’t need to use Hooke’s (note the spelling!) law. If you know how to answer the question correctly (see below)...

That’s one way of thinking about it. But I’m not convinced that is the intended interpretation. The ionisation energy of a molybdenum K-electron is 20.0keV, so the K-electron energy level would be -20.0 keV. Why use the value 27.5keV? I think it’s just a badly written question. I hope it’s not...

This is (IMO) a badly written question for another reason. The final state of the atom is ambiguous. Is it: a) missing only an L-electron? (call this state-1)? or b) missing a K-electron and an L-electron (call this state-2)? For an answer to be possible with the given data, I think we need to...

Here’s a strategy to find the final state: 1) Calculate the amount of energy (A) needed to warm the ice to 0 deg.C. 2) Calculate the amount of energy (B) needed to melt the ice at 0 deg.C. 3) Calculate the amount of energy (C) lost by the water if it cools to 0 deg.C. 4) Calculate the amount...

@palaphys, for an intuition, it helps to visualise flux lines. In the following diagram, the magnitude of the flux through the loop due to a charge +Q is ‘3 lines’. For convenience, we can take ‘enter loop on left and leave loop on right’ as the positive sense here. This is equivalent to...

Yes, you’re right. I had (badly) misunderstood the nature of unacademy. It is not linked to NTA. It appears to be a (fairly large, established) educational company - but definitely not an authoritative source. Apologies for the confusion. I had found this earlier...

In that case I agree with your values for the magnitudes of the fluxes. Though I would write '2/10' as '1/5'! Imagine lines of flux as lines leaving a positive charge or entering a negative charge (image from https://eee.poriyaan.in/topic/electric-flux-11760/): If lines of flux pass through...

Hi. A few thoughts… You haven’t given the radius of the ring. You haven’t mentioned how you have dealt with the charge of 2q on the ring. There's no way for us to check these without the radius of the ring. What do you think? Hint: how would you find the individual and total fluxes through...

As I understand it, NEET (UG) is an entrance examination set by the Indian National Testing Agency (NTA) for entrance to medical degrees, Study-material is provided by the NTA. This is a link to the study material covering ‘Power of a Lens’...