Recent content by stretch851

So when finding the force, would mass =ball+rod? Okay so angular velocity is change in angular position/change in time. so it'd 2radian/.1558s=13.45 radians/s. a=v^2/r, 13.45^2/.65m=278.46 I=mr^2, 2.72kg*(.65m)^2=1.14 angular acceleration = a/r, 278.46/.65m=428.40 torque=I * angular...

The rod is accelerating around it's axis(another rod is spinning and providing torque). My question is how fast must the axis(rod) spin and/or how much torque must be produced. This question leads into gear ratios but I understand that stuff mostly.

Homework Statement A 2.72kg ball is attached to a .65m rod that weighs 1.24kg. The rod rotates around it's axis 125 degrees. After rotating 125 degrees the ball is let go from the rod. How much torque is required to make the ball's exiting velocity 18m/s. Homework Equations t=F*d vf=vi...