Thanks. That helps until I get to the end of part B, again. For the equation, I get:
T= R(e^(-ht/c)-1)/-h
Seems reasonable.
Then, when I plug in the values, I get the equation to be -1250(e^(-.02t)-1)
When I graph, it seems alright, but then the problem asks me to predit T at times 10, 20, 50...
I'm getting dT/dt = (R+hT)/C as my differential equation. Correct?
rate of heat lost to room= -hT
R=C(dT/dt) - hT
R+hT=C(dT/dt)
...
but then when I try to do part B, I get really confused and the math is very long. I'm pretty sure I get the wrong answer. And the C's are confusing since I used to...
Homework Statement
This is the most confusing problem I have ever seen in my life. I just plain do not know what it's saying and what exactly a proportionality constant is.
When you turn on an electric heater, such as "burner" on a stove, its temperature increases rapidly at first, then...