Recent content by strikemaster

Thanks. That helps until I get to the end of part B, again. For the equation, I get: T= R(e^(-ht/c)-1)/-h Seems reasonable. Then, when I plug in the values, I get the equation to be -1250(e^(-.02t)-1) When I graph, it seems alright, but then the problem asks me to predit T at times 10, 20, 50...

I'm getting dT/dt = (R+hT)/C as my differential equation. Correct? rate of heat lost to room= -hT R=C(dT/dt) - hT R+hT=C(dT/dt) ... but then when I try to do part B, I get really confused and the math is very long. I'm pretty sure I get the wrong answer. And the C's are confusing since I used to...

Homework Statement This is the most confusing problem I have ever seen in my life. I just plain do not know what it's saying and what exactly a proportionality constant is. When you turn on an electric heater, such as "burner" on a stove, its temperature increases rapidly at first, then...