Recent content by Student149

Thanks for the reply. I too couldn't find much on what seems like an obvious/standard problem, hence the Q :(. I am fine with approximations with some margin of error (if we know any). I do understand the 3D part problem but I was hoping we have some idea of rough approximations (for a standard...

any comments ??

I think (though I am not sure) the magnetic field on one end is given by: $${B_{\rm end} = \frac{\mu n I}{2\sqrt{L^2+(R+Kw)^2}}}$$ But I am not sure how this translates (and changes with distance/time) to force and the time (t0) required to travel a distance (d0) since the field must change...

Consider 2 similar solenoids/electromagnets with appropriate iron core with the following parameters: core Length (L), core Radius (R), electromagnet wire diameter (w), number of turns of wire/winding layer on the core (L/w), number of layers of winding (K), total number of turns ((L*K)/w)...

This has been very helpful. Thanks a ton again.

I totally understand. But how do we know about the same spin probability of each case ↑↑ and ↓↓ given arbitrary α, β?

Got it. But if we limit ourselves to a plane (which I was assuming as its in the video example hence the confusion) we can set ##\phi##=0 in #21 then from it we can get the probability of opposite spin. But, it doesn't answer about the probability of ##\uparrow \uparrow## and ##\downarrow...

Now I am terribly lost to the point of giving up any hope of understanding even the basics unless I have a complete formal background in physics. The original Q was regarding arbitrary ##α, β## and I assumed there is only one angle ##θ## (as described in the video). I have no clue about the...

So, just to be clear/reconfirm: if Alice and Bob have 1 particle each and Alice decides to measure its particle (in a direction that has an angle ##\theta## with the original direction ##z##) the probability of both Alice and Bob getting a ##\uparrow \uparrow## and getting a ##\downarrow...

1. I picked my example from here: 2. The ##- (\frac 1 2 )\cos \theta## is twice. Hence, it cancels ##+\cos \theta## 3. If the direction of measurement is at an angle ##\theta## w.r.t. the original direction vector the probability of spin up or down in that new direction (it can be...

I am confused. I think they do add to 1 in #9. Please elaborate what is flawed in #1 (I am a novice in QM, but I can't find a flaw)

I would. much appreciated.

Thank you. I would be thankful..

haha. That is why it was a guess. I stated that assuming non zero real values. I am not sure how to compute the generic case hence the Q?

We know that Bell States follow the Rotational Invariance property i.e. the probability of results on measurement of two entangled particles do not change if the initial measurement basis (say ##u##) is rotated by an angle θ to a new basis (to say ##v##). Lets take the Bell State ##\psi = \frac...