Recent content by student333

ΔL = (mg)/k = (0.48*9.8)/600 = 0.00784 m but this doesn't match up with the given solution of 0.0125 m :confused: Is 0.00784 the equilibrium position, and I am supposed to find the max distance past that point, perhaps? The question seems a bit vague to me, so I don't have a good grasp on...

Does the spring exert a force of -ky on the mass? At equilibrium shouldn't this be equal to mg? How does this relate to the answer to the problem? If I set them equal and solve for y, I don't get the proper answer, so it seems that I'm missing something.

Homework Statement The elastic constant of a spring holding an object in equilibrium is 600 N/m. Find the extension of the spring with respect to its initial length if the object has a mass of 480 g.Homework Equations hooke's law: F = -kyThe Attempt at a Solution I know that the answer is...