Ok that does help - so we should be looking at bisulfate rather than sulfuric acid
but wouldn't the concentration of bisulfate be the same i.e. the second part of the henderson hasselbach would still be
for a. log (0.05/0.1) = log(0.5)
and for
b. log(0.1/0.5) = log(0.2)
I feel like i'm...
THe answer is supposed to be (B) but I'm not understanding properly
I initially chose A - to form an alkaline buffer, the # mol of acid should be half of this. But this doesn't seem to be the case
I don't understand why the mol of base in this case should be 5x the mole of acid
your help is...
Aha! missed that, thank you
ok so then that means the distance travelled according to the traveller is:
6.5c \times 24 \times 365 \times 60^2 = 6.14 \times 10^{16} m
when the person is in motion, how is the 6.5 ly being interpreted ? Is the noninertial observer seeing a shorter'length that...
If we took the perspective of the space traveller themselves, they are stationary and the whole universe goes past them at 0.7c. THen th elapsed time of 6.5 yr looking outside is
\Delta t =6.5 \frac{1}{\sqrt{1-0.7^2}} = 9.11 yrs
THen, when the traveller looks at the person travelling at 0.9c...
If we draw a punnet square, it would look like this
Male on horizontal
Female on vertical
Cb
Cb
Cw
CbCw
CbCw
Cw
CbCw
CbCw
Does this mean that the offspring will have a blend of both black & white hair i.e. grey? Or is there something that is being missed here?
Sorry about this. Added that question as well
Further to Mark44's comment, the answer I got still seems to be double counting the 7x7, 14x14, and so on
Is it as simple as dividing the result by two ?
There are 14 integers between 1 to 100 that are divisible by 7
If we used indirect approach, then we would do the total number of possibilities C(100,2) = 4,950
and subtract all nubmers that are indivisible by 7 : C(100-14, 2) = C(86,2) = 3,655
the difference of these two numbers is 4,950 -...
I'm sort of stumped here , do i do this?
(1+3x) \left( \frac{1+3x}{1+2x} \right)^2 = (1+3x) \left( \frac{3}{2} - \frac{1}{2(2x+1)} \right)^2
(1+3x) \left( \frac{3}{2} \right)^2 \left( 1 + \frac{-1}{3(2x+1)} \right)^2
and then apply the binomial theorem formula on the squared term above...
We don't need to worry about the n = -1 so we can assume that the function is continuous on any interval [a,b] where a, b are real numbers
if I separate my interval into N partitions, then the right side values in my interval are
a + \frac{b-a}{N}, a + 2 \frac{b-a}{N}, ... , a + k...
The question of this assignment is to compare and contrast the three methods. I have a set of points that describe the flow rate of a blood pumped by a heart.
I have studied numerical methods in a 2nd year course but it's been a while so much refresher is required. I have been using Numericals...
This isn't a homework question per se but I can post more details like the data points & my work after.
Suppose we are given a set of arbitrary points for which we cannot find an equation and we need to find the area under the curve without an analytical method - we can use either of the three...
I believe that my usage of the Bayes formula (A|B) might be throwing you off.
The question statement is " An urn is selected at random & a coin is drawn from the urn. If the selected coin is silver, what is the probability that urn III was selected"
if using the formula, would it be the 1/2...
From my understanding of Bayes formula, it should look like something like this
P(Silver| III) = \frac{P(III | silver) \times P(silver)}{P(III)}
now we know that P(urn III) = 1/3
and the probability of P(silver) = Pr(silver|urn I) + P(silver|urn II) + P(silver|urn III) = 1/3 (0) + 1/3 (1/2)...