ok, lets apply this formula!
what does it change ?
as far my thinking goes-
this integral simply adds up the product of elemental charges with the function next to them, now take for instance this ##\rho(r')## describes charge density for a sphere of radius ##R##. Now in the interior of the...
The volumetric charge density is given as
$$\rho(r) = \rho_0 \left(1 - \frac{ar}{R}\right)$$
What shall be the Electric field at any distance ##r## ?
My approach was to directly use the coulomb's law and integrate with respect to volume.
$$ \mathbf{E}(\mathbf{r}) = \frac{1}{4\pi\epsilon_0}...