Recent content by suma

first, i am not sure but i have some question on this. why is that the trace is being taken on the dimension of hilbert space to calculate Ωs, isn't hilbert space a number rather than a matrix. trace acts on matrix. i think the best to check all of 3 options and see whether they agree, then...

i think that any two quantities x and y once appears with equality equation like that should have solution

let's take dy = k dx/dt where k is a constant, can then the value of y in terms of x or vice versa be solved? i think it is possible to solve this, asking the physics and mathematicians who have encountered such problem mathematicians help out here! thanks

hi, is it possible to solve the following equation, dy = dx/dt for relation between y and x? thanks

thanks, but what is the meaning of visibility? does visibility means chance of seeing interference? is the V in your equation the visibility? there is a minus sign in the intensity form are L(x) and R(x) operators? thanks

Hi, What does visibility in interference mean? in quantum mechanics? V = Imax-Imin/Imax+Imin but which part of the interference does Imax and Imin refer to? thanks

When we say expectation value of an operator like the pauli Z=[1 0; 0 -1], like when <Z> = 0.6 what does it mean? What is difference between calculating expectation value of Z and its POVM elements{E1,E2}? thanks

hi, thanks i understand now

Hello, What does less than one photon mean? 0.5 or 1/2 photon what does it mean?

hi, this was just an example, the main question is whether states can be derived from density matrix thanks

(1 0)'*(1 0) = (1 0; 0 0), ok but if (a1 a2)'*(a1 a2) = (1 0; 0 0) and in general case there is no solution to find a1 and a2, is this correct? thanks

Is it not possible to deduce quantum states from a density matrix?

I have few questions to ask: 1. Can a photon state be written as |ψ> = [cos(θ) sin(θ) exp(i*ø)] in column vector form 2. When a general photon state|ψ> = [cos(θ) sin(θ) exp(i*ø)] passes through a linear polarizer [1 0; 0 0] we get [cos(θ) 0] at the output but not [1 0] as is usually...