Recent content by Sunay_

I think the idea is to be able to analyze mathematical objects using calculus. If you take derivative of some function and it gives two different results how will you interpret it? In order to use calculus you have to have well-defined functions.

I tried to imply that if ## x+1 = \log_{a}{abc} ## then ## \frac{1}{x+1} = \log_{abc}{a} ## The same is true for ##\log_{abc}{b}## and ##\log_{abc}{c}## So, because ## \log_{abc}{a}+\log_{abc}{b}+\log_{abc}{c}=\log_{abc}{abc}=1 ## is true, The solution can be found using this: I hope I...

If ## x = \log_{a}{bc} ## Then ## x+1 = \log_{a}{bc} + \log_{a}{a} = \log_{a}{abc} ## We can equate all the arguments in this way namely abc and then turn it into base by taking reverses. So, ##\frac{1}{x+1}+\frac{1}{y+1}+\frac{1}{z+1} = 1## and this gives the desired equality.

I think this solution is fairly easy ## (z+\frac{1}{z})^2 = -3+4i ## Then ## z^2+2+ \frac{1}{z^2} = -3+4i ## if you subtract 4 from both sides it is ## (z-\frac{1}{z})^2 = -7 + 4i ## Now we know what ##(z^2-\frac{1}{z^2})^2## is and from here it can easily be calculated.

Hi, I am Sunay. I am a huge science enthusiast and have a bachelors degree in mathematics. Nice to meet you all!