Recent content by SuperCup

I can't believe this didn't occur to me. I'm feeling pretty silly :f Thankyou so much!

Oops! My bad, I'll look out for that in future. Okay, so if I do it right, I get: 2(1-x) = \sqrt8(x) And then 2 - 2x = \sqrt8(x) ... Uh, I still don't know how to go on from there to get x = \frac{2}{(\sqrt8 + 2)}, as the textbook says I should end up at. The "solving the quadratic" bit...

This is a question that I'm doing as part of revision for my January mocks. Being bad a algebra in general, I'm stuck. The answer is a worked example and I still don't understand it, so I'm feeling very silly. Homework Statement Charges of +4C and +8C are placed 1.00m apart. At what...