Recent content by superhero241

so.. what to do?

It never specifies, but if you're close it accepts it. Is there any other way to solve it? I really need your help

The question is only asking for acceleration of M1. Aren't we calculating the acceleration for both that way?

It still says incorrect. The question is almost due and I don't know where the error is coming from.

I edited it, and I got 4.65 m/s^2. Is that the correct answer?

Ok it's a calculator error, but still not the right answer. 231.3*9.8 = 2266.74 Even if I do (2266.74)/(167+231.3) = 5.69 m/s^2 It's not the right answer still

This problem is so frustrating. After so many attempts, and my answer is still wrong. please tell me where I am messing up. Fgrav = mg = 231.3(9.8) = 2266.74 N so ∑F=Mtotal*a (2266.74-413.11) = (167 +231.3)*a a= 4.65 m/s^2 I am only trying to find the acceleration of M1...therefore I am...

Oh, I should subtract the two forces to get a net force?

so Fgrav = mgsin52 = 231.3(9.8)sin52 = 1786.22 N so ∑F=Mtotal*a (1786.22-413.11) = (167 + 231.3)*a a = 3.45 m/s^2 ? It's not recognizing my answer still

Gravity.

so ∑F = 413.11? if not, how do I find the force on M2?

It's giving me the coefficient of kinetic friction for M1. So I do: Fk = Muk*N Fk = 0.41(167)(9.8)cos52 = 413.11 N Then, to find the acceleration, I use the F = ma equation. so you said add the two masses for m. 413.11 = (167+231.3) a a = 1.04 m/s^2 but it's wrong

I don't understand. So I add the 2 masses in the first set and second set of equations?

I'm solving on the last problem. Sorry for the confusion. I am using the second set of equations to solve for acceleration of M1.