Recent content by Suzie

Thank you, there is not exactly what I needed, but it helped me to understand at least part of it. I still don't see how to get from those projection operators from Bjorken&Drell to my expression.

No, it is true only without the sum over s. Now I see there might have appeared small misconception: the "s" on the left side is not the same "s" as on the right side of the equality. On the right side, the "s" is four vector. For example, in particle's rest frame, \begin{equation} s = (0...

Hello everyone, I have a problem with deriving following equality: \begin{equation} u^{s}(p) \bar{u}^{s}(p) = 1/2 ((\slashed{p} + m)(1+\gamma^5 \slashed{s})) \end{equation} where s is spin 4-vector. I know how to calculate this tensor product when there is spin sum in front of it, but without...