Recent content by sylent33

Ah I see now,writing out like that makes it really simple. I did not know how to deal with that. Thanks a lot for the help PS: I plotted both of these functions and you can clearly see at which value they are the same,and that the solution in the book is correct.

Im a having trouble understanding how this exactly works. $$ |x^2 - 4| < |x^2+2| $$ So I know the usual thing to do when you have absolute values,here it is even simpler since the right part of the inequality is always positive so I just have these 2 cases. 1. ## x^2-4 >= 0 ## and 2. ## x^2-4...

Makes sence,also I see the x squared as well now.Thanks for the help as always

Hello! Consider this partial differential equation $$ zu_{xx}+x^2u_{yy}+zu_{zz}+2(y-z)u_{xz}+y^3u_x-sin(xyz)u=0 $$ Now I've got the solution and I have a few questions regarding how we get there. Now we've always done it like this.We built the matrix and then find the eigenvalues. And here is...

As arhzz stated var is just the unit for the reactive power,thought that wasnt anytinh too out of the ordinary.halo gentrafo is the halogen transformator from a),I guess in the translation google ate some words and it came out like that. And the quation was a latex error I wanted to type in ##...

Hi everybody; With a halogen transformer with the data U = 230 V, f = 50 Hz, I = 1.5 A and cos ϕ = 0.35 a reactive power compensation can be carried out with a parallel capacitor Cp. ¨ (a) Calculate the value of Cp to achieve a power factor cos ϕk = 0.9. I did that like this; First I...

Oh,so I overcomplicated as per usual. And that about the notation is confusing but in our notations its how i proposed; if Q1 is acting on Q2 than it is F12. I am sticking to that. Thanks for the help!

After working with this formula I get to the right equation. But I was wondering if I could have simply gone off the fact and said; F12 is pointing right so its positive,F32 is pointing left so its negative? And just set up the equation like that Thanks!

Oh I think I get it now. I need to take into account the direction of the vectors. Now simply using the fact that I need F32 to be negative for my equation to work out I can say F12 - F32 = 0 and than it would all work. But how would/should I determine the direction generally? Also as Bvu...

Hi, I assume you are referring to the c) task and to my statement F12 + F32 = 0 ? I am not sure what exactly you mean with "remember they are vectors" ? Are you implying that I should add them like I would 2 vectors? X component with X Y with Y etc?

Hi! Given three voltages as follows; Q1 = 1C,Q2 = 1C,Q3 = 2C The distance a is 1m and b = 2m a) Find the values of the forces that are acting on Q2 I did that like this; $$ F_{12} = \frac{Q1*Q2}{4\pi\epsilon r^2} $$ $$ F_{32} = \frac{Q1*Q3}{4\pi\epsilon r^2} $$ The results are ...

So as I have seen just know I didnt realize that the RL in b and a was diffrent.My apologies. I did it just know and it should be RL = 9,25 Ohm.Now using the hint from Steve and this new RL I get the result I wanted (if we plug it into the formula I used earlier).But I am interested in the...

Ah okay that I kind of overlooked.I've tried it again; Now looking at your formula I think that the values of Ri and RL are simply the ones I calculated; so after calculating I again it should be I = 1,11 A . Now I think this should be the current of the circuit.Now to get the power of the...

Okay so This is what I've tried; a) A formula I've found in the lecture notes; $$ U_a = U_q - R_i*I $$ To get I used the ## I = \frac{P}{U} ## formula I get I to be 0,46 A.Now put back in formula for and rearange to get Ri should be $$ \frac{Ua-Uq}{I} = Ri $$ and the solution should be 0,43...

OKay of "gauge theory" I hafve never heared,but that explanation is what I was looking for thanks!