Recent content by T531

Okay, so v(of x) = -160/m v(of y) = -60/m 1.0x10^4 J = (m)*[(160/m)^2+(60/m)^2] 1.0x10^4 J = m*(25600/m^2 + 3600/m^2) = 29200/m 1.0x10^4 J*m=29200 m=2.92kg then do I use KE = mv^2 ? if so 1.0x10^4 J = (2.92kg)v^2 therefore v = 58.5 m/s then v(of x) = -160/m = -160/(2.92 kg) = -54.8m m/s...

Homework Statement A bomb at rest with 1.0x10^4 J explodes into three pieces. The first piece is 1.0 kg and travels in the positive y direction with a velocity of 60 m/s. The second piece is 4.0 kg and travels in the positive x direction at 40 m/s. Find the third piece's mass, velocity, and...