balancing redox
Interesting question. I balanced it a different way, please tell me why this is not correct:
recognizing that the Cl2 is beibg both oxidized and reduced:
2e- + 2Cl ---> 2Cl-, and
2Cl ---> 2Cl(+5) + 10e-
the ration being 1:5, so
5Cl2 + 6OH- ---> 9Cl- +...