Recent content by tanaygupta2000

Okay I finally got the mentioned answer by considering one Stokes line and other Anti-Stokes. I constructed following equations: ##(E_1+P) - E_0## = hc/(3430 A) ##(E_1+P) - E_2## = hc/(2670 A) Solving these two equations (subtracting them and substituting values of ##E_0## and ##E_2##) finally...

Thanks a lot for clearing my doubt sir. Can we suppose that the first line be Rayleigh and second be Stokes? In that case we can write ##(E_0 + P) - E_0## = Energy corresponding to 2670 ##Å## ##(E_0 + P) - E_1## = Energy corresponding to 3430 ##Å## Solving these two equations, giving me the...

Thanks for the response, sir. The question might be incomplete or incorrect, as I too felt I require additional information to proceed. I consider to approach the first question as, since we bombarded photons of energy ##P## at the molecule and given that we obtain the Raman lines at these two...

I know that for the vibrational Raman spectrum, the energy levels are given by- E(n) = ℏω(n+1/2) - χℏω(n+1/2)^2 But I'm not getting what does it meant by the Raman lines are observed at given values of wavelengths and the fundamental vibrational frequency. I equated the E(0) with the energy...

Thank You for the guidance. Much appreciated!

TL;DR Summary: Theoretical astrophysics research status in ISRO, India I am from India and want to be an astrophysicist serving my nation. Whenever I check about any ISRO news, it is always about some engineering achievements, like the launch vehicle and never about pure theoretical research...

I am able to prove that it is 0.225 but how do I prove that it is also 0.414? I need to find the max. and min. packing fraction values, which I got as a function of (r1/r2) Please help

Yes sir, sorry I meant ##^{2N}C_{N-1}## number of ways are possible for 2N spins.

Yes sir. Can I follow this approach: For two spins => 1/2 + 1/2 = 1 way For four spins => (-1/2) + 1/2 + 1/2 + 1/2 = 4 ways since minus sign can be on any of the 4 spins For six spins => (-1/2) + (-1/2) + 1/2 + 1/2 + 1/2 + 1/2 = 15 ways of arranging minus signs Likewise, for 2N spins, total no...

To the extent I understood this question, we have to enumerate the total no. of ways to get a total of spin S = 1 from 2N number of spin-1/2's. Now, I think that by spin-1/2's, the question is referring to s1 = s2 = 1/2 (and not something like 3/2, 5/2, ...). When N = 1, we have 1/2 + 1/2 => No...

Thank You so much for your help.

I tried this way and got struck after this. Please guide.

Please help!

Yess! It very well worked! Lots of Thanks.

But I think a and a' only act on |n>. Or should I use this property for coherent states: a|α> = α|α> <α|a' = α*<α|