How Do You Operate the Hamiltonian on a Coherent State?

AI Thread Summary
The discussion focuses on operating the Hamiltonian of a displaced harmonic oscillator on a coherent state |α>. The confusion arises from the presence of position and momentum operators in the Hamiltonian, which seem incompatible with treating α as a constant. Participants suggest using raising and lowering operators to express position and momentum, and clarify that |α> is not the same as |n>, the energy eigenstate. The conversation emphasizes the need to differentiate between the original and displaced Hamiltonians and suggests that finding the ground state of the displaced Hamiltonian may require completing the square in the Hamiltonian. Understanding the relationship between α and |α> is crucial for solving the problem.
tanaygupta2000
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Homework Statement
For α = f/(ω√2mћω), evaluate H|α> for H = p^2/2m + mω^2x^2/2 - fx, which is the Hamiltonian of a displaced Harmonic Oscillator under a constant force f. Is this |α> the ground state of this displaced simple harmonic oscillator?
Relevant Equations
H|α> = En|α> = (n + 1/2)ћω |α>
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I am getting that we have to operate the given Hamiltonian on the given state |α>. But what is confusing me is that since this H contains position and momentum operators which just involve variable x and partial derivative, how do I operate this H on the given α, since it seems like α is essentially a constant quantity? Please help!
 
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tanaygupta2000 said:
Homework Statement:: For α = f/(ω√2mћω), evaluate H|α> for H = p^2/2m + mω^2x^2/2 - fx, which is the Hamiltonian of a displaced Harmonic Oscillator under a constant force f. Is this |α> the ground state of this displaced simple harmonic oscillator?
Relevant Equations:: H|α> = En|α> = (n + 1/2)ћω |α>

View attachment 280440

I am getting that we have to operate the given Hamiltonian on the given state |α>. But what is confusing me is that since this H contains position and momentum operators which just involve variable x and partial derivative, how do I operate this H on the given α, since it seems like α is essentially a constant quantity? Please help!

Have you been through the exercise of defining the "raising and lowering" operators for the harmonic oscillator? If so, then you should know that ##x## and ##p## can be expressed as linear combinations of the raising and lowering operators.

Alternatively, if you solve the harmonic oscillator in position space, then you should know that the state satisfying ##H |a\rangle = (n+1/2)\hbar \omega |a \rangle## can be expressed in the position basis as a function of ##x##. That's a lot more complicated way to go, so I'm assuming that you are using the raising and lowering operators...
 
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stevendaryl said:
Have you been through the exercise of defining the "raising and lowering" operators for the harmonic oscillator? If so, then you should know that ##x## and ##p## can be expressed as linear combinations of the raising and lowering operators.

Alternatively, if you solve the harmonic oscillator in position space, then you should know that the state satisfying ##H |a\rangle = (n+1/2)\hbar \omega |a \rangle## can be expressed in the position basis as a function of ##x##. That's a lot more complicated way to go, so I'm assuming that you are using the raising and lowering operators...
Yes, sir! I am very much familiar with the representation of position and momentum operators in terms of raising and lowering operators:
x = √(hbar/2mw) (a' + a)
p = i√(mhw/2) (a' - a)

where x and p are position and momentum operators and a and a' are creation and annihilation operators.
 
But I think a and a' only act on |n>.
Or should I use this property for coherent states:
a|α> = α|α>
<α|a' = α*<α|
 
Please help!
 
tanaygupta2000 said:
But I think a and a' only act on |n>.
Or should I use this property for coherent states:
a|α> = α|α>
<α|a' = α*<α|

##|a\rangle## is the state ##|n\rangle##. It's not a coherent state. Your "relevant equation" says:

##H |a\rangle = (n+1/2) \hbar \omega |a\rangle##

There is some confusion here, because you're using the same symbol, ##H## to mean both the original hamiltonian and the "displaced" hamiltonian. What I assumed that the problem was asking for was

Let ##H_0 = p^2/2m + m \omega^2/2 x^2##.
Let ##|n\rangle## be a state such that ##H_0 |n\rangle = (n+1/2) \hbar \omega |n\rangle##.
Let ##H = H_0 - fx##.

Then what is ##H |n\rangle## in terms of the original basis, ##|n\rangle##?

So under this interpretation of the question, ##H|n\rangle = ## some combination of states ##|0\rangle, |1\rangle, |2\rangle,...##
 
IMG_20210330_192651.jpg


I tried this way and got struck after this. Please guide.
 
I think that that’s as much as you can do. The ground state of the displaced Hamiltonian cannot be equal to ##|n\rangle##, since acting on it by the Hamiltonian mixes states of different ##|n\rangle##.

You could try to find the ground state of the displaced Hamiltonian, but that’s going beyond what the problem asked for.
 
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Thank You so much for your help.
 
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tanaygupta2000 said:
I am getting that we have to operate the given Hamiltonian on the given state |α>. But what is confusing me is that since this H contains position and momentum operators which just involve variable x and partial derivative, how do I operate this H on the given α, since it seems like α is essentially a constant quantity? Please help!
I had the same question when I read the problem statement. What is the relationship between ##\alpha## and ##\lvert \alpha \rangle##? Have you asked your instructor for clarification?

I think your interpretation that the question is about coherent states of the harmonic oscillator may be correct. In that case, the state ##\lvert \alpha \rangle## satisfies ##\hat a \lvert \alpha \rangle = \alpha \lvert \alpha \rangle##. You can find ##E_0##, the energy of the ground state of the displaced harmonic oscillator, by completing the square in the Hamiltonian.
 
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