Recent content by Tapias5000

This is what I have been able to advance, I am concerned if the declining factor of 4/3 is actually correct ...

@pasmith I tried another approach obtaining the following, I do not know if it is correct \begin{array}{l}\int_{ }^{ }\frac{1}{\sqrt{x^3+1}}dx\\ \int_{ }^{ }\left(x^3+1\right)^{-\frac{1}{2}}dx\\ \left(1+u\right)^R\ \ \left[u=x^3,\ R=-\frac{1}{2}\right]\\ f\left(u\right)=\left(1+u\right)^R\\...

Where did you get the last equation from? ## \left(\frac{\beta}{g(x)}\frac{dg}{dx}\right)f ##

what I did was the following, even though I am sure this is incorrect. ## I=\frac{1}{\sqrt{1+x^a}} ## ## \frac{dI}{dx}=-\frac{ax^{a-1}}{2\left(1+x^a\right)^{\frac{3}{2}}},\ \ \frac{d^2I}{dx^2}=-\frac{ax^{a-2}\left(-ax^a-2x^a+2a-2\right)}{4\left(x^a+1\right)^{\frac{5}{2}}} ## ##...

How do I obtain p (x) and q (x) ?, I had done similar exercises but in that case I did it from the solution already given ... oh i got to solve the edo ## \frac{d^2I}{dx^2}+\frac{dI}{dx}+I=0 ## and then replace?

I also don't understand how to get the descending factorials for this hypergeometric series, I also know that there is another way to write it with gamma functions, but in any case how am I supposed to do this? If I write it as a general term, wolfram will give me the result which leaves me...

My solution is However can someone explain in detail why will be equal to the weight? and why does it have to be multiplied by 6?

waat, Can you tell me the name of this method?

My solution is now I am asked for the same result but in this form but I don't know where to start.

damn I suck at this lmao I think it's better if I just give up and that's it. Do you have any video on yt that you can share with me to illustrate what you mean?

Should I look up the definition of the center of mass for a cone?

no, I really couldn't understand it, can you show me a different example?

aaa already understand. you mean the formula ## h / 4 ##? If I replace values I do not get the same result so I assume that I am missing some concept If you solve the integral in the form of its symbols, I will obtain the "formula" for this case, right?

Hmm, the problem tells us to locate the centroid of the area shaded in blue in Z, and according to the figure that is a known data from 0 to 2, right? There are several formulas, so I would not know which one to apply here.

ummm I don't understand what you mean by this, could you give me another example? I saw that there were several formulas depending on the case, but I doubt that my professor would like me to use them.