Recent content by tdreceiver17

-T+mg=mv^2/r ?

Thats what I thought at first but wanted to try something new. So is it the same thing I have put down but with a plus sign?

Sorry for the size of the pic. If you click on it it will expand.

Homework Statement The maximum tension the string can have without breaking is Tmax. Derive an expression for Vmax, the maximum speed the ball can have at point Q without breaking the string. Homework Equations F=ma Vc=(mv^2)/r T=mg+ma The Attempt at a Solution I thought I could do...

ah my bad I was correcting it as you answered . so is it 2=mAc so its 2 g ? the answer choices only come in a number times g

So I set it up as Sum of forces = T-mg=Ac 6-4=Ac 2?

An object weighing 4 Newtons swings on the end of a string as a simple pendulum. At the bottom the swing, the tension in the string is 6 Newtons. What is the magnitude of the centripetal acceleration of the object at the bottom of the swing.Centripetal Acc. = v^2/r Sum of forces =...

i found it really easy to just multiply it all out and put it in your calculator. you will see that it only has 2 x intercepts

My question is how do you find the acceleration if you don't know the Tension. If someone could just elaborate on the question as a whole it would be very helpful. I didn't really know anything about how to do this problem.

Ok so I have this problem which is most likely easy to all of you. The problem says that the first 10 meters of the 100 meter are covered in the first 2 seconds by a sprinter who starts from rest and accelerates with a constant acceleration. The remaining 90 meters are run with the same velocity...