Recent content by teage

s=ut+(1/2)at^2 u= 4m/s; t= 1 1/3s; a=3/ms^2 s=8m For m1, it is traveling vertically upward, contributing to the braking torque. i don't understand how the height that it is at effects the force it contributes to braking. or which height to use. The only height i have is the stopping...

sorry, second pic is here..i'm having no luck with uploads here.. please excuse that

Thanks for the input, the drum inertia was a given and the 8m is what i was using for potential energy(using kinematic equations solving for theta). Do i use the distance to stop when calculating the potential energies? I've tried again this morning using a different method method calculate...

sorry about the image being 90 degrees off optimal! it was the right way when i viewed it earlier.

Homework Statement I have a problem involving a goods lift with a cage m1 = 1500kg which is raised at V = 4m/s via a winding drum with a radius of 0.6m with the help of a counter weight of m = 900kg. i am asked to find the braking torque required to bring it to rest in 1 1/3 seconds. Also i am...

Acceleration is now irrelevant. It has been accelerated and is traveling at a steady 4 m/s. have found the power required to accelerate using the total torque multiplied by omega. My question is which torque value out of the 3 do I need in order to calculate the power required for constant...

Hi guys, I am designing (homework) a winch drum and am having a brain fart. i am trying to find the power required to maintain a constant velocity. i have figured out that the torque required to lift the mass is in 3 parts: 1. torque to accelerate the drum = 241 N.m 2. torque required to...