Wow... A+ for getting my post the heck out of dodge.
Calculators are permitted; but I can't get mine to cooperate. There is a "Trigonometric Functions of Special Angles" table in our textbook and I see that the sin pi/3 = (square root 3)/2, and that cos pi/6 = (square root 3)/2.
Sine my...
Sorry... I just read that this forum isn't for getting homework help. But I don't know how to move this post, so if somebody in here could help me, I'd appreciate it.
How do I solve:
[sin (pi/3)] + [cos (pi/6)]? <--- "pi" is 3.14...
I think that [sin (pi/3)]= (square root 3) divided by 2
AND that [cos (pi/6)]= (square root 3) divided by 2.
Now I can't remember how to add fractions containing square roots.
My textbook...