- #1
teffany
- 5
- 0
How do I solve:
[sin (pi/3)] + [cos (pi/6)]? <--- "pi" is 3.14...
I think that [sin (pi/3)]= (square root 3) divided by 2
AND that [cos (pi/6)]= (square root 3) divided by 2.
Now I can't remember how to add fractions containing square roots.
My textbook says the answer is: square root 3.
I just have NO IDEA how to get there.
Please help! Thanks in advance.
[sin (pi/3)] + [cos (pi/6)]? <--- "pi" is 3.14...
I think that [sin (pi/3)]= (square root 3) divided by 2
AND that [cos (pi/6)]= (square root 3) divided by 2.
Now I can't remember how to add fractions containing square roots.
My textbook says the answer is: square root 3.
I just have NO IDEA how to get there.
Please help! Thanks in advance.