Recent content by TexasBB12

would a velocity of 15.04 be correct for this?

25=.707vi x (.707vi/4.9) ??

vi=13.16??

vertically t=vysintheta/4.9 so 25=vi- vysintheta/4.9?? I'm just really needing to figure this out as I'm on a time crunch

25m=0+vi(t) +1/2axt2 so i have t=25/vcostheta, this is where i don't know how to solve for time

vx=vcos45 vy=vsin45 distance is 25m The problem is set up so i can't use energy to solve for the velocity the only equation i can really think of is vf2=vi2+2ax would i solve for the y component using a=-9.8??

Homework Statement Launch a .8 kg ball from a spring cannon in order to hit a target 25m away, the cannon fires at 45 degrees relative to the ground, what is the initial velocity necessary for the ball to make the distance. spring constant is 425 N/m. Homework Equations fspring=-kx...