I already graphed it
for |x+1| there will be two lines intersecting at the point -1 and for the other curve we are having the the head of the curve at (-1,6) and it is opening downword
okay |x+1| consists of x+1, -x-1
once we use x+1=-(x+1)2 +6
x= 1, x= -4
and when we are using -x-1= -(x+1)2 + 6
we get x=-2, x=3
now we are having 4 points of intersection
soo how would we get the limits
Homework Statement
find the Area Bounded by the two curves, y=|x+1|, y= - ( x+1)2 + 6
Homework Equations
y=|x+1|, y= - ( x+1)2 + 6
The Attempt at a SolutionA= Integration of | f (x) - g(x) |
x+1= f(x)
-(x+1)2 + 6= g(x)
getting the limit of integration:
x+1= - (x+1)2 + 6
x2 + 3x - 4=0...
Homework Statement
"for a cantilever beam with a concentrated load in the middle of the span, prove that
the slope is WL2/8EI, and the deflection is 10WL3/96EI"
Homework Equations
the length of the span is L, the concentrated load is acting in the middle at L/2
The Attempt at a...