Oh, ok. I ended up getting 2z as well.
But what doesn't make sense to me is that the original value should have no i (imaginary number) in it since we're taking the modulus. But after simplifying it, we get 2zm which would still have i in it.
Hi there.
I need help simplifying the following:
|\sqrt{z^2 -1} +z| + |\sqrt{z^2 -1} -z|
What I did was I rewrote z in polar coordinates, but I ran into some difficulties taking the square root of r^2(cos2θ-sin2θ)-1.
I also tried rewritting z in exponential form, but also had problems. Help?