Recent content by thee qs

if at R2 , we have 8volts = 2 ohm *i and i isolate i , then i=4 i = 8 / 2 +6 , so i = 1 amp after R3 where are you going with this, i tought we needed to calculate the equivalent resitance value for the entire circuit , then isolate for the last one , using the total...

god, i had the right answer all along, and been trying for 3 days to understand people explaining to me the incorrect answer so apparently i was right all along folks, should of trusted my judgement first

well the correct answer was D. which is the answer i withe method i had used. and this question counted for 1% of my final grade... well thx

nope , correct answer is -1 apparently , and that question counted for 1% of my final grade... so why -1 ?

(2*10^-2) N / 1000metre= ((4π*10^-7) i ^2 ) / 2π *1 or * 0.5 ) since distance between the wire is 1 metre . so diameter is 1 meter , r should be half that, so 0.5 so if r =1 and L = 1000 meters ---> i = 10 amps if r=1 and no value for L then i = 316 amps if r= 0.5...

ty!

8=6i so 8/6 = 4/3 , would be the current through R3

1/0 doesn't exist . having cos 90 at denominateur will make the entiere fraction divided by 0 . even then , it would mean C would be the answer which it isn't , and since it isn't D . it has to be A.

so helical step increases and radius decreases from 0 to 90 degrees, and from 90 to 180 degrees , helical step decreases and radius increases no?

sin 90 = 1 cos 90 = 0 , so 1/0 no good from 0 to pi ,( 0 to 180 ) mouvement is upwards and from pi to 2 pi, goes downward...? ? hmmm wait , cos 180 is -1 , sin 180 is 0 from 0 to 90 , sine increases, , cosine decreases and from 90 to 180 , since decreases, cosine increases

tangent sin / cos = tangent , so both v cancel out , leaving tangent in the numerator, thus eliminating 2 choices , no?

i calculatd the current on this worksheet

amp meter reads 2 amps , after the unknow resistance . which is the same junction after R3 . as you can see from the arrows , initial guess for the current flow , suggest that after R2 , current would go on through R3 , then R1 and then to the battery R2 and R3 are in series , so their...

ohhhhhh , is the answer C !? i think it is...

well the problem stated here is quite vague , and here are the formulas found in the book, for a force between 2 parallele current can either be attractive or repulsive depending if the current is oriented in the same direction . So i gather the amount of force is the same , with only the...