Recent content by therealnihl

Most physical systems are chaotic. The double pendulum is the sort of canonical example, but look in any textbook on analytical mechanics and they usually have numeros examples of chaotic mechanical systems. One of the more explicit connections between physics and chaos is the concept of entropy.

The way I started to get an intuition about physics is whenever I was bored I would look at all the mechanical phenomena around me and try to explain it using physical concepts (you do not have to do actual calculations) How am I walking? What forces are responsible for giving the torque on my...

You right in the sense that the work done (∫Fpulldy) by the pulling force is equal to the net increase in total mechanical energy. But the total work done (∫Fnetdy) on the rope is equal to just the net increase in the kinetic energy. This can be seen if you replace ∫Fnetdy by: ∫Fpulldy -...

For the record, I think PeterO's response was way better than my own; since he explained the physical reason as to why amplitude is not related to frequency/period/angular frequency. Which is the whole point of learning physics (to gain a physical intuition rather than merely look for equations...

Unless we are misunderstanding the question, what PeterO is implying by "good reason" is since there is no equation relating period and amplitude, changing the amplitude has no effect on the period or the angular frequency. You intuition that doubling the amplitude has to have some effect is wrong.

Yeah solution 1 is silly because m is not constant, and F=ma assumes constant mass, so the more general form dp/dt = Fnet is necessary. The problem is when I do this method I get λv2 + λyg = Fpull (I showed the dp/dt = Fnet solution and the work-energy solution to my GSI and he still can't...

Well assuming the kinetic energy is of the form: \frac{1}{2}mv2, the the period for small oscillations is 2π√(k/m) where, k is the second derivative of the potential energy function evaluated at the equilibrium position (you might have to take the limit as it goes to the equilibrium position in...

There a two sufficient conditions to prove something is simple harmonic oscillator F = -kx or Etotal = \frac{1}{2}Av2+\frac{1}{2}Bq2. Where A and B are some constants and, q is some coordinate (in your case ax). Then the period is T = 2π√(A/B) Also since it says small oscillations, I would...

Its true that if velocity is linear with respect to time, then the average velocity can be treated as a constant velocity. Its also true that if acceleration is linear with respect to time, then the average acceleration can be treated as a constant acceleration. But in the case of the spring...

Ok, so if I do it from the power perspective the power is: P = d(\frac{1}{2}m(y) * v2 + m(y) * λg\frac{y}{2}) / dt P = d(\frac{1}{2}λyv2 + \frac{1}{2}λgy2) / dt P = \frac{1}{2}λ(dy/dt)v2 + λgy(dy/dt) dy/dt = v, by definition, so: P = \frac{1}{2}λv3 + λgyv So does that mean my second...

To find the moment of inertia of the sphere, they had to sum the moment of inertia of many tiny disks of mass dm. The moment of inertia of a disk of mass M is (1/2)MR^2. To see a derivation of the moment of inertia of a disk: http://mikebloxham.com/H7A/I%20for%20sphere.pdf

Check your signs, but your equations look correct. Since you have two equations and two unknowns it is a solvable system of equations. If you need helping solving the system, I would use substitution or you could try elimination.

Hmm, what is big M and W?

Homework Statement A uniform rope of mass λ per unit length is coiled on a smooth horizontal table. One end is pulled straight up with constant speed v0 Find the force exerted on the end of the rope as a function of height y and find the power delivered to the rope. Homework Equations...