Recent content by ThomasJR
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
I can fix that confusion but can you help me clarify my result.. Thanks a lot!- ThomasJR
- Post #20
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
Sir, this is what started off with, now please tell me if i did everything correct. I will be thankful to you guys truly. so here's what i started off with. 202.31/(1+e^(3.938-0.314t)... Now i set x=3.938-0.314t, du=-0.314, revised du= -644.299. Next i set that integral up. -644.299...- ThomasJR
- Post #19
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
OMG ok i got it... so now my final integral u-ln|u|?- ThomasJR
- Post #17
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
OK so now i have (1+e^x-e^x)/(e^x+1), now i set u=e^x+1 du=e^x, now i set up my integral u-(u-1)/u and it gives me 1-1+Ln|u|... Please tell me if this is right... I feel suicidal right now because this thing is due Thursday :(- ThomasJR
- Post #16
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
Let me get this right. So i have this original function (1/((e^x)+1), i multiply the top and bottom by 1+e^x-e^x, and then simplifying i have, (1+e^x-e^x)/((1+e^x)... So now i set u= 1+e^u-e^u ? is this what you are saying?- ThomasJR
- Post #13
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
1=1+e^u-e^u,... wait where did this come from?- ThomasJR
- Post #11
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
ok so now I have 1-e^u/(1+e^u), if i make any more substitutions i will b totally lost. Can somebody please do this problem step by step- ThomasJR
- Post #9
- Forum: Calculus and Beyond Homework Help
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Expanding exponential fucntions
I want to see how you guys expand it because i am stuck with a calculus integration problems which asks me to use u-substitution. Integrate , 1/(1+e^x) Without using partial functions- ThomasJR
- Post #4
- Forum: Calculus and Beyond Homework Help
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Expanding exponential fucntions
Homework Statement Expand (1+e^(2x)), and (1+e^x)^2. Are they any different. I am confused please help Homework Equations The Attempt at a Solution- ThomasJR
- Thread
- Exponential
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
It can be done without using parts!- ThomasJR
- Post #7
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
Yes i went to wolfram mathematica too, and got the same setp as you did here, however, i am not suppose to use partial function at this point, i am bounded by Parts and U-substitution :( The next thing i did was multply the top and bottom by 1+e^u-e^u, and cancel out like terms which leads me...- ThomasJR
- Post #5
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
Oh yes, i factored out the constant, then i set u= 3.938-0.314x, and du=-0.314 which gets me 1/(1+e^(u)... :( I'm not sure how to integrate this now! Please help me- ThomasJR
- Post #3
- Forum: Calculus and Beyond Homework Help
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How to integrate (202.31)/(1+e^(3.938-0.314x)).
Homework Statement Calculate the antiderivative of the following: (202.31)/(1+e^(3.938-0.314x)) using either U-substitution or Parts but NOT partial functions. Homework Equations please show to me your work The Attempt at a Solution I'm not sure how to approach this, I'm stuck- ThomasJR
- Thread
- Integrate
- Replies: 20
- Forum: Calculus and Beyond Homework Help