Recent content by tiagomendes

thx thx for the name any idea when it will be available for people to use??

yh i just can imagine myself filling up the screen with things jumping around and its just great :)

If anyone has comments or knows about similar programs I am glad to hear about it

I will give anything to get my hands on this program. I bet my physics teacher would enjoy it too

Watch this i found it very amazing anyone know the name of the program??

Hello, i asked my Math teacher about this question and showed him the various methods which you guys had shown me and he said that we haven't gotten so far yet in vectors and gave me a hint which was to put the three vectors in a equation. What i did was the following : a= | 3 | b= |5 |...

Could you tell me which values you put in the equation to help me understand it?

Isnt it true that A set of points is said to be COPLANAR if and only if they lie on the same geometric plane THREE points are ALWAYS COPLANAR. Could i use this statement to answer the question?

Ill have a think about it ill get back to you later and thank you :)

I don't know how to use Matrixs because i haven't really learned about them... But considering My problem how would i input the data into this formula (axb)c=0 my answer always gives something else :S

I have been looking on the internet to find methods on how to work out linear independency but i haven't found any, any that i understand. do you happen to know any tutorials for this that are simple to understand

oh wait... i completely misread... i understood you said it isn't as in the question isn't coplanar :P lol sorry

hmm then it means there is a mistake in my textbook... Grrr i hate when tht happens so i wasn't misusing the formula god :P just wasted 3 hours of my time but atleast i know the problem :) thanks for your help

Thank you ill have a go at it... And i just realized something... this is in the wrong forum right?

Prove that the vectors a=3i+j-4k b= 5i-3j-2k c= 4i-j-3k are COPLANAR Homework Equations (axb)c=0 The Attempt at a Solution If (axb)c=0 then c is orthogonal to axb and therefore c is in the plane...