Recent content by TimelessTime

Ok, so I found the average acceleration to be 7.3 x 10^3 however, the direction I got was 75degrees N of W. Here's what I did: |Vx| = 21 m/s(cos22) - 26 m/s(cos22) = -4.64 m/s |Vy| = 21 m/s(sin22) + 26 m/s(sin22) = 17.6 m/s aav,x = -4.64/0.0025 = -1856 m/s^2 aav,y =...

alright, ill try solving it again and post if there's anymore problems. Thanks for the help.

so what the problem is is that for the x components the should both be positive and for the y components it is a subtraction?

These were my calculations: |Vx| = |Vfx| + (-|Vix|) = 21 m/s(sin68) - 26 m/s(cos22) = -4.6 m/2 oops, i got -4.6 but on the next page i left out the negative, not sure if that is the real problem though |Vy| = |Vfy| + (-|Viy|) = 21 m/s(cos68) - 26 m/s(sin22) = -1.9...

Problem: A hockey puck rebounds from a board as shown in figure 16. The puck is in contact with the board for 2.5 ms. Determine the average acceleration of the puck over the interval. t = 0.0025 s |vi|= 26 m/s |vf| = 21 m/s aav = ? *v and a are vectors* I have made several attempts to...