Recent content by Tj Nelson

Okay. If the weight of the rocket were less than the thrust, then I assume we would not be able to lift it off.

Ok so the forces are opposing each other at liftoff so ΣFy = Ft- mg =ma . But it does not make sense to me how you can get the time it takes to liftoff from that.

The thrust has to be greater than the force of gravity acting on it for the rocket to get off the ground, which is true in this case.

Homework Statement A rocket with an initial mass of 60,000kg ignites its engines and burns fuel at a rate of 300 kg/s with an exhaust velocity of 2220 m/s. How long after the engines start does the rocket lift off the ground? Homework Equations From Newton's second law F = Ma this equation can...