How long does it take for a rocket to lift off the ground?

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Homework Help Overview

The problem involves a rocket's lift-off dynamics, focusing on the relationship between thrust, weight, and the time it takes for the rocket to leave the ground. The subject area pertains to classical mechanics, specifically Newton's laws of motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conditions necessary for lift-off, including the relationship between thrust and gravitational force. There are attempts to derive the time to lift-off based on forces acting on the rocket, and questions about the necessity of integrating equations to find the change in velocity.

Discussion Status

The discussion is ongoing, with participants exploring the implications of thrust exceeding weight and questioning how to determine the exact time of lift-off. Some guidance has been offered regarding the conditions for lift-off, but no consensus has been reached on the method to calculate the time.

Contextual Notes

Participants note that the initial weight of the rocket and the thrust produced by the engines are critical factors in determining lift-off, and there is an acknowledgment of the complexity introduced by varying these parameters.

Tj Nelson
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Homework Statement


A rocket with an initial mass of 60,000kg ignites its engines and burns fuel at a rate of 300 kg/s with an exhaust velocity of 2220 m/s. How long after the engines start does the rocket lift off the ground?

Homework Equations


From Newton's second law
F = Ma this equation can be derived
M(dv/dt) = Fext + u(dm/dt)

The Attempt at a Solution


I think the solution is fairly simple. What I did is divide by m, Fext = mg, and integrated it to get
ΔV = uln(mi/mf) - gΔt. But we don't know what the velocity of the rocket...
 
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There is no need to integrate the equation to find change in velocity. You are only interested in when the rocket lifts off the ground.

What is the condition on the amount of thrust in order for the rocket to start moving upward?
 
The thrust has to be greater than the force of gravity acting on it for the rocket to get off the ground, which is true in this case.
 
Right.
 
Ok so the forces are opposing each other at liftoff so ΣFy = Ft- mg =ma . But it does not make sense to me how you can get the time it takes to liftoff from that.
 
If the thrust force is greater than the weight of the rocket when the engines are first turned on, then how long do you have to wait before the rocket lifts off?

(This would have been a more interesting problem if the initial weight of the rocket were less than the thrust.)
 
Okay. If the weight of the rocket were less than the thrust, then I assume we would not be able to lift it off.
 
Tj Nelson said:
Okay. If the weight of the rocket were less than the thrust, then I assume we would not be able to lift it off.
Not at first. But if you wait ...
 

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