Recent content by tn3003

OK I see it now. The distance for Q above should be 7.75"/2 = 3.875" I was using the centroid of the whole shape, which gave me 7.75" - 5" = 2.75" and that's wrong. Thank you PhanthomJay for not giving out the answer and let me figure it out myself. I really appreciate it.

Homework Statement This is the cross sectional are of the shape: http://img38.imageshack.us/i/shapep.jpg/" It's made of 2 10"x1" plates. (Picture is not to scale) Q (first moment of inertia) above and below the neutral axis should be the same. For some reasons, my calculated Q above is...